simple question

N of boxxys cousins are in a room together. What is the chance that at least two of the cousins that are present in the room share the same bday?

Well, it's SO simple.

The chance is equal to 365Pn divided by 365 to the power of n
for n of boxxys cousins do not share a bday
therefore the probability you are looking for is 1 minus this value
a proof of this is as follows
for the first cousin they can have any of the 365 days in a year as a birthday without sharing it with another
for the second it is 364 divided by 365
and the third it is 363 divided by 365 et cetera
now we have the series 365 over 365*364 over 365 * so on and so on * (365 (n-1)) over 365
which is equal to 365! over (365-n)!*365^n
as n! over (n-r)! nPr this is the same as 365Pn over 365^n


inb4 cool story bro

This only works in theory. Take a group of people and try this formula out on them.

cool story bro